Solution is prepared by dissolving 50g of NaCl (MM= 58.44g/mol) in 50g of H2O (MM = 18g/mol). The volume of the solution is 63.3 ml. Find mass % of solute, m, M, N of the solution. (M-molarity, m-molality, N-normality)
Solution:
Mass of NaCl = 50 g
The molar mass of NaCl is 58.44 g/mol
Mass of H2O = 50 g = 0.05 kg
The molar mass of H2O is 18.00 g/mol.
The volume of the solution is 63.3 ml (0.0633 L).
Mass % of solute (NaCl):
The mass/mass percent (%m/m) is defined as the mass of a solute divided by the mass of a solution times 100.
%m/m = (mass of solute / mass of solution) × 100%
Mass of solution = Mass of NaCl + Mass of H2O = 50 g + 50 g = 100 g
Mass of solute (NaCl) = 50 g
Hence,
Mass % of solute = (50 g / 100g) × 100% = 50%
Mass % of solute = 50%
Molarity (M):
Molarity or molar concentration is the number of moles of solute per liter of solution.
Molarity of solution = Moles of solute / Volume of solution
Moles of NaCl = Mass of NaCl / Molar mass of NaCl = 50 g / 58.44 g mol-1 = 0.8556 mol
Hence,
Molarity of solution = 0.8556 mol / 0.0633 L = 13.5166 mol/L = 13.5 M
Molarity of solution = 13.5 M
Molality (m):
Molality of a solution is the moles of solute divided by the kilograms of solvent.
Molality of solution = Moles of solute / Kilograms of solvent
Mass of solvent (H2O) = 0.05 kg
Hence,
Molality of solution = 0.8556 mol / 0.05 kg = 17.112 mol/kg = 17.1 m
Molality of solution = 17.1 m
Normality (N):
Normality is a measure of concentration equal to the gram equivalent weight per litre of solution.
Normality = Mass of solute / (Volume of solution × Equivalent weight)
Equivalent weight = Molar mass / n
n = 1 (for NaCl)
Equivalent weight = 58.44 g mol-1 / 1 = 58.44 g mol-1
Hence,
Normality of solution = 50 g / (0.0633 L × 58.44 g mol-1) = 13.516 N = 13.5 N
Normality of solution = 13.5 N
Answers:
Mass % of solute = 50%
Molarity of solution = 13.5 M
Molality of solution = 17.1 m
Normality of solution = 13.5 N
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