For a solution of acetic acid (HC2H3O2) to be called vinegar it must contain 5% acetic acid by mass. If the vinegar is made up of only of acetic acid, density of the solution = 1.006g/ml. Find mol fraction of solute and solvent, M, m of the solution.
Solution:
Vinegar is an aqueous solution of acetic acid.
acetic acid - HC2H3O2 = C2H4O2
The molar mass of C2H4O2 is 60.052 g/mol.
The molar mass of H2O is 18.015 g/mol.
Let's assume that the volume of the solution is 1 L (1000 mL).
Thus,
Mass of 1 L C2H4O2 solution = Solution volume × Density = 1000 mL × 1.006 g/mL = 1006 g
Mass of C2H4O2 = (%C2H4O2 × Mass of solution) / 100% = (5% × 1006 g) / 100% = 50.3 g C2H4O2
Mass of solvent (H2O) = Mass of solution - Mass of C2H4O2 = 1006 g - 50.3 g = 955.7 g H2O
Moles of C2H4O2 = Mass of C2H4O2 / Molar mass of C2H4O2 = 50.3 g / 60.052 g mol-1 = 0.8376 mol
Moles of H2O = Mass of H2O / Molar mass of H2O = 955.7 g / 18.015 g mol-1 = 53.0502 mol
Mole Fraction (χ):
Mole fraction (χ) is the ratio of moles of one substance in a mixture to the total number of moles of all substances.
Total number of moles = Moles of C2H4O2 + Moles of H2O = 0.8376 mol + 53.0502 mol = 53.8878 mol
χsolute = χC2H4O2 = Moles of C2H4O2 / Total number of moles = 0.8376 mol / 53.8878 mol = 0.016
χsolute = 0.016
χsolvent = χH2O = Moles of H2O / Total number of moles = 53.0502 mol / 53.8878 mol = 0.984
χsolvent = 0.984
Molarity (M):
Molarity or molar concentration is the number of moles of solute per liter of solution.
Molarity of solution = Moles of C2H4O2 / Volume of solution
Molarity of solution = 0.8376 mol / 1 L = 0.8376 mol/L = 0.8376 M = 0.838 M
Molarity of solution = 0.838 M
Molality (m):
Molality of a solution is the moles of solute divided by the kilograms of solvent.
Mass of solvent (H2O) = 955.7 g = 0.9557 kg
Molality of solution = Moles of C2H4O2 / Kilograms of solvent
Molality of solution = 0.8376 mol / 0.9557 kg = 0.8764 mol/kg = 0.8764 m = 0.876 m
Molality of solution = 0.876 m
Answers:
χsolute = 0.016
χsolvent = 0.984
Molarity of solution = 0.838 M
Molality of solution = 0.876 m
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