Calculate the volume (in dm3) of 1.50 mol.dm-3 H2SO4 necessary to react completely with 2.000 g CuO according to the equation below.
CuO + H2SO4 → CuSO4 + H2O
n = m/M
M (CuO) = 79.545 g/mol
n (CuO) = 2.000 / 79.545 = 0.025 mol
C = n / V
V = n / C
According to the equation, n (CuO) = n (H2SO4).
V (H2SO4) = 0.025 / 1.5 = 0.017 L or dm3
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