Answer to Question #179789 in Chemistry for Lester Salguera

Question

What is the molarity of a 1.5 L solution containing 80.02g of sodium hydroxide.

Answer 1

Solution:

sodium hydroxide - NaOH

Moles of NaOH = Mass of NaOH / Molar mass of NaOH

The molar mass of NaOH is 39.997 g mol^-1.

Hence,

Moles of NaOH = (80.02 g) / (39.997 g mol^-1) = 2.00 mol

Molarity of NaOH = Moles of NaOH / Liters of solution

Hence,

Molarity of NaOH = (2.00 mol) / (1.5 L) = 1.33 mol/L = 1.33 M

Molarity of NaOH = 1.33 M

OR (short form solution):

(80.02 g NaOH) × (1 mol NaOH / 39.997 g NaOH) × (1 / 1.5 L) = 1.33 M NaOH

Answer: The molarity of NaOH solution is 1.33 M.