Answer to Question #178778 in Chemistry for Karley Eilts

Question

What is the new freezing point of a 0.50 m solution of a nonelectrolyte dissolved in water?

Answer 1

Solution:

The freezing point depression (ΔT_f) is related to the molality (m) and the freezing point depression constant (K_f) by ΔT_f = K_f × m (for nonelectrolyte).

K_f(water)=1.86˚C/m

m = 0.50 m

Hence,

ΔT_f = (1.86˚C/m) × (0.50 m) = 0.93˚C

Water normally freezes at 0˚C.

Hence,

Freezing point = 0˚C - 0.93˚C = -0.93˚C

Freezing point = -0.93˚C

Answer: The new freezing point of a solution is -0.93˚C.