Answer to Question #175377 in Chemistry for klj

Question

How much Ca₃(PO₄)₂(s) could be produced in an industrial process if 55.00 g of CaCl₂ in solution reacted completely with sufficient Na₃(PO₄)(aq)?

Answer 1

According to the reaction:

3CaCl₂+ 2Na₃(PO₄) = Ca₃(PO₄)₂ + 6NaCl

From here, the mass of Ca₃(PO₄)₂ equals:

m(Ca₃(PO₄)₂) = m(CaCl₂) × Mr(Ca₃(PO₄)₂) / (Mr(CaCl₂) × 3) = 55.00 g × 310 g/mol / (111 g/mol × 3) = 51.2 g

Answer: 51.2 g