Answer to Question #175298 in Chemistry for Kate

Question

Calculate the pH of a solution with a [OH-] = 3.0 x 10-6

Answer 1

Solution:

We can convert between [OH^-] and pOH using the following equation:

pOH = - log[OH^-]

pOH = - log(3.0×10^-6) = 5.52

pOH = 5.52

 

For any aqueous solution at 25^∘C:

pH + pOH = 14

pH = 14 - pOH = 14 - 5.52 = 8.48

pH = 8.48

Answer: pH = 8.48