Answer to Question #174605 in Chemistry for Antonio

Question

How many grams of aluminum chloride will be produced from 255 moles of Cl2

Answer 1

Solution:

The balanced chemical equation:

2Al + 3Cl₂ → 2AlCl₃

According to the equation above: n(Cl₂)/3 = n(AlCl₃)/2

n(AlCl₃) = 2 × n(Cl₂) / 3 = (2 × 255 mol) / 3 = 170 mol

Moles of AlCl₃ = 170 mol

Mass of AlCl₃ = Moles of AlCl₃ × Molar mass of AlCl₃

The molar mass of AlCl₃ is 133.5 g mol^-1.

Hence,

Mass of AlCl₃ = 170 mol × 133.5 g mol^-1 = 22695 g

Mass of AlCl₃ = 22695 g

OR (short form solution):

(255 mol Cl₂) × (2 mol AlCl₃ / 3 mol Cl₂) × (133.5 g AlCl₃ / 1 mol AlCl₃) = 22695 g AlCl₃

Answer: 22695 grams of aluminum chloride (AlCl₃) will be produced.