A sample of drinking water has a nitrate concentration 2.3 ppm (a level that is safe to drink). Calculate the mass, in grams, of nitrate ions in a 250 mL glass of this water.
According to the definition of ppm (parts per million), 1 ppm = 0.001 g / 1000 mL = 1 mg/L.
From here, 250 mL of water contains:
m(nitrate) = 1 mg/L × 0.25 L × 2.3 ppm = 0.575 mg = 5.75 × 10-4 g
Answer: 5.75 × 10-4 g
Comments
Leave a comment