How many grams of NaN3 are required to produce 12.0 ft3 of N2 if the gas has a
density of 1.25g/L?
2NaN3 = 2Na + 3N2
12.0 ft3 = 340 l
n (N2) = V/22.4 = 340 / 22.4 = 15.2 mol
According to the equation, n (NaN3) = 2/3 x n (NaN2) = 2/3 x 15.2 = 10.1 mol
n = m/M
m = n x M
M (NaN3) = 65 g/mol
m (NaN3) = 10.1 x 65 = 657.7 g
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