Answer to Question #173381 in Chemistry for seng

Question

How many grams of NaN₃ are required to form 1.00 g N₂?

Answer 1

Solution:

The balanced chemical equation:

2NaN₃(s) → 2Na(s) + 3N₂(g)

According to the equation above: n(NaN₃)/2 = n(N₂)/3

Moles of N₂ = Mass of N₂ / Molar mass of N₂

The molar mass of N₂ is 28.0134 g mol^-1.

Hence,

n(N₂) = 1.00 g / 28.0134 g mol^-1 = 0.0357 mol

n(NaN₃) = 2 × n(N₂) / 3 = (2 × 0.0357 mol) / 3 = 0.0238 mol

Mass of NaN₃ = Moles of NaN₃ × Molar mass of NaN₃

The molar mass of NaN₃ is 65.0099 g mol^-1.

Hence,

Mass of NaN₃ = 0.0238 mol × 65.0099 g mol^-1 = 1.547 g = 1.55 g

Mass of NaN₃ = 1.55 g

Answer: 1.55 grams of NaN₃ are required.