a chemist mixed 100 ml of 10%(w/v) hydroiodic acid, 100 ml of 2 molar sulfuric acid and 40 grams of potassium permanganate. how much molecular iodine will be produced?
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Expert's answer
2012-10-24T10:55:14-0400
So we have 100 * 0.1 =10 g of HI it is 10/128=0.078125 mol ,we also have 100*2/1000= 0.2 mol of H2SO4 and 40/158=0.25316 mole ,as can we see H2SO4 and KMnO4 is in excess.
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