. A 50.0-mL sample of gas is cooled from 119°C to 80.0°C. If the pressure remains constant, what is the final volume of the gas?
V1 = 50.0 mL
T1 = 119°C + 273 = 392 K
P1 = P2 = const
V2 = unknown
T2 = 80.0°C + 273 = 353 K
Solution:
Since the pressure doesn't change, Charles' Law can be used.
Charles' Law can be expressed as: V1 / T1 = V2 / T2
V1T2 = V2T1
To find the final volume, solve the equation for V2:
V2 = V1T2 / T1
V2 = (50.0 mL × 353 K) / (392 K) = 45.0255 mL = 45.0 mL
V2 = 45.0 mL
Answer: The final volume of the gas is 45.0 mL.
Comments
Leave a comment