A natural gas tank is constructed so that the pressure remains constant. On a hot day when the temperature was 33°C, the volume of gas in the tank was determined to be 3000.0 L. What would the volume be on a warm day when the temperature is 11°C?
V1 = 3000.0 L
T1 = 33°C + 273 = 306 K
P = const
V2 = unknown
T2 = 11°C + 273 = 284 K
Solution:
Since the pressure doesn't change, Charles' Law can be used.
Charles' Law can be expressed as: V1 / T1 = V2 / T2
V1T2 = V2T1
To find the final volume, solve the equation for V2:
V2 = V1T2 / T1
V2 = (3000.0 L × 284 K) / (306 K) = 2784.3137 L = 2784.3 L
V2 = 2784.3 L
Answer: V2 = 2784.3 L.
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