Answer to Question #169432 in Chemistry for Phyroe

Question

Since reaction velocity is doubled for approximately 10°C-degree rise in temperature, how much faster does a reaction proceed at 100°C than at 20°C?

Answer 1

The change in temperature equals:

ΔT = 100 °C - 20 °C = 80 °C.

Since reaction velocity is doubled for the 10°C-degree rise in temperature, the reaction proceeds (80 °C / 10 °C) × 2 = 16 times faster.

Answer: 16