Answer to Question #169075 in Chemistry for Rebecca Lindsay

Question

What is the volume in litres of 6 × 1023 gaseous molecules at standard temperature and pressure?

Answer 1

Solution:

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Moles of gas = (6×10²³ gaseous molecules) × (1 mol / 6.022×10²³ molecules) = 0.996 mol of gas

At STP, one mole of any gas occupies a volume of 22.4 L.

Thus 0.996 mol of gas occupies:

(0.996 mol × 22.4 L) / 1 mol = 22.32 L of gas

0.996 mol of gas occupies a volume equal to 22.32 L.

Answer: The volume of 6×10²³ gaseous molecules is 22.32 liters.