Answer to Question #168959 in Chemistry for Isha

Question #168959

Calculate the mole fraction of each component of the solution containing 65g of ethanol (C2H5OH) in 350g of water.


1
Expert's answer
2021-03-05T03:29:45-0500

χ(A)=n(A)n(A)+n(B)100\chi (A)=\frac{n(A)}{n(A) + n(B)} * 100% %

χ(H2O)=m(H2O)/M(H2O)m(H2O)/M(H2O) + m(C2H5OH)/M(C2H5OH)100\chi (H2O)=\frac{m(H2O)/M(H2O)}{m(H2O)/M(H2O) \ +\ m(C2H5OH)/M(C2H5OH)} * 100% %

χ(H2O)=350/18350/18 + 65/46100\chi(H2O) = \frac{350/18}{350/18 \ +\ 65/46} * 100% % = 93.23%

χ(C2H5OH)=100\chi(C2H5OH) =100 % - χ(H2O)\chi(H2O) = 100%-93.23% = 6.77 %


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