Answer to Question #168753 in Chemistry for Jada

Question

Number of moles of sodium carbonate in 250cm3

Answer 1

n = m/M

M (Na₂CO₃) = 106 g/mol

density = m/V

m = density x V

density (Na₂CO₃) = 2.54 g/cm³

m (Na₂CO₃) = 2.54 x 250 = 635 g

n (Na₂CO₃) = 635 / 106 = 6 mol