Answer to Question #168753 in Chemistry for Jada

Question #168753

Number of moles of sodium carbonate in 250cm3

Expert's answer

n = m/M

M (Na₂CO₃) = 106 g/mol

density = m/V

m = density x V

density (Na₂CO₃) = 2.54 g/cm³

m (Na₂CO₃) = 2.54 x 250 = 635 g

n (Na₂CO₃) = 635 / 106 = 6 mol

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