Answer to Question #167005 in Chemistry for Kylie

Question

How many grams are there in 1.3 x 1023 molecules of BCl3

Answer 1

Solution:

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Moles of BCl₃ = (1.3×10²³ molecules of BCl₃) × (1 mol / 6.022×10²³ molecules) = 0.2159 mol BCl₃

Moles of BCl₃ = Mass of BCl₃ / Molar mass of BCl₃

Mass of BCl₃ = Moles of BCl₃ × Molar mass of BCl₃

The molar mass of BCl₃ is 117.17 g mol^-1.

Hence,

Mass of BCl₃ = 0.2159 mol × 117.17 g mol^-1 = 25.294 g

Mass of BCl₃ = 25.294 g

Answer: 25.294 grams are there in 1.3×10²³ molecules of BCl₃.