Answer to Question #165930 in Chemistry for oxygen molecules are in 3.36 L of oxygen gas

Question

How many oxygen molecules are in 3.36 L of oxygen gas at STP

Answer 1

Solution:

At STP, one mole of any gas occupies a volume of 22.4 L.

Thus 3.36 L of oxygen (O2) gas correspond to:

Moles of oxygen = 3.36 L × (1 mol / 22.4 L) = 0.15 mol

Moles of oxygen = 0.15 mol

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Oxygen molecules = (0.15 mol of oxygen) × (6.022×10²³ molecules / 1 mol) = 9.033×10²² O₂ molecules

Oxygen molecules = 9.033×10²² O₂ molecules

Answer: 9.033×10²² oxygen molecules are in 3.36 L of oxygen gas at STP.