Answer to Question #165796 in Chemistry for Ava Brooke

Question

A 5.60 gram sample is heated to an initial temperature of 100 ^oC. The sample is then placed in a calorimeter containing 71 grams of water starting at 24 ^oC. If the final temperature is 27 ^oC what is the specific heat of the sample?

s_H2O = 4.18

Answer 1

Q= C x m x deltaT

s_H2O = 4.18 J/(kg °C)

Q_(water) = 4.18 x 0.071 x (27-24) = 0.9 J

C = Q/(m x deltaT) = 0.9/(0.0056 x (100-27)) = 2.2 J/(kg °C)