To dilute 150 ml of 1 F CaCl2 solution to 0.02 F would require how many milliliters of water?
CM = n/V
n1 = n2
CM1 x V1 = CM2 x V2
1 x 0.150 = 0.02 x V2
V2 = (1 x 0.150)/0.02 = 7.5 L = 7 500 ml
The required amount of water is: 7 500 - 150 = 7 350 ml
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