determine the volume of .0100M NaOH needed to titrate 20mL of .400M HCl
NaOH+HCl=NaCl+H2O
n (NaOH)=n(HCl)=CM x V
0.0100 x V (NaOH) = 0.400 x 20
V (NaOH) = (0.400 x 20)/0.0100 = 800 ml
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