Question

1452 mL of nitrogen is at 1.8 atm and 287 K.  What is the new temperature if the volume increases to 1500. mL and the pressure decreases to standard pressure?

Answer 1

According to the combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

where P₁, V₁ and T₂ - initial pressure, volume and temperature, respectively; P₂, V₂, T₂ - final pressure, volume and temperature, respectively.

From here:

T₂ = P₂V₂T₁ / P₁V₁ = 1 atm × 1500 mL × 287 K / (1.8 atm × 1452 mL) = 164.7 K

Answer: 164.7 K