Answer to Question #160826 in Chemistry for mina

Question

What is the molarity of a 85% H2SO4 solution with a density of 1.2 g/mol?

Answer 1

Density = 1.2 g/mL

Solution:

85% mass of H₂SO₄ means 85 g of H₂SO₄ in 100 g solution.

Density of solution = Mass of solution / Volume of solution

Hence,

Volume of solution = Mass / Density = (100 g) / (1.2 g mL^-1) = 83.33 mL = 0.08333 L

Molarity = Moles of solute / Volume of solution = Mass / (Molar mass × Volume of solution)

The molar mass of H₂SO₄ is 98 g mol^-1.

Molarity = (85 g) / (98 g mol^-1 × 0.08333 L ) = 10.4086 mol/L = 10.4 M

Molarity of a 85% H2SO4 solution is 10.4 M.

Answer: The molarity of a 85% H₂SO₄ solution is 10.4 M.

OR:

Molarity = (w × d × 10) / M

where,

w = amount of solute

d = density of solution

M - molecular mass of solute

Molarity = (85 × 1.2 × 10) / 98 = 10.408 M

Molarity of a 85% H₂SO₄ solution is 10.4 M.

Answer: The molarity of a 85% H₂SO₄ solution is 10.4 M.