How many grams of Li2Cr2O7 are in a 10.0 L solution with a molarity of 0.150 M Li2Cr2O7?
According to the equation:
M = n / V = m / (Mr × V)
where M - molarity, n - number of moles, V - volume, m - mass, Mr - molecular weight
From here:
m = Mr × V × M = 230 g/mol × 10.0 L × 0.150 mol/L = 345 g
Answer: 345 g
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