Answer to Question #159849 in Chemistry for moriah

Question

If 7.50 g of methane gas (CH) is in a 3250 mL container at 25° C, what is the pressure inside the container?

Answer 1

According to the ideal gas law:

pV = nRT = m/RTMr

where p - pressure, V - volume, n - number of moles, R - gas constant, T - temperature, m - mass, Mr - molecular weight.

From here:

p = m/RTMrV

Here, m = 7.50 g, V = 3250 ml = 3.250 l, T = 25° C = 298.15 K, R = 0.082 L atm / mol K, Mr(methane) = 16.04 g/mol

As a result:

p = 7.50 g / (0.082 L atm / mol × 298.15 K × 16.04 g/mol × 3.250 l) = 0.006 atm

Answer: 0.006 atm