Answer to Question #159843 in Chemistry for moriah

Question

What volume will 0.75 moles of Oxygen gas (O2) occupy at 30°C and a pressure of 52.7 kPa?

Answer 1

According to the ideal gas law:

pV = nRT

where p - pressure (52.7 kPa = 0.52 atm), V - volume, n - number of moles (0.75 mol), R - gas constant (0.082 L atm / mol K), T - temperature (30 °C = 303.15 K)

From here:

V = nRT / p = (0.75 mol × 0.082 L atm / mol K × 303.15 K) / 0.52 atm = 35.8 L

Answer: 35.8 L