Answer to Question #159664 in Chemistry for make

Question

what mass of bromine will be produced if a potassium bromide solution reacts with 60.0mL of a 1.30mol/L solution of acidified NaCIO4

Answer 1

Solution:

The balanced chemical equation:

4H₂SO₄ + NaClO₄ + 8KBr → NaCl + 4H₂O + 4Br₂ + 4K₂SO₄

According to the equation above: n(NaClO₄) = n(Br₂)/4

Moles of NaClO₄ = Molarity of NaClO₄ × Solution volume

Moles of NaClO₄ = 1.30 mol/L × 0.06 L = 0.078 mol

n(Br₂) = 4 × n(NaClO₄) = 4 × 0.078 mol = 0.312 mol

Moles of Br₂ = Mass of Br₂ / Molar mass of Br₂

Mass of Br₂ = Moles of Br₂ × Molar mass of Br₂

The molar mass of Br₂ is 159.808 g mol^-1.

Hence,

Mass of Br₂ = 0.312 mol × 159.808 g mol^-1 = 49.86 g

Mass of Br₂ = 49.86 g

Answer: 49.86 grams of bromine (Br₂) will be produced.