How could you prepare 250 ml 0.20M using only a solution of 1.0M NaCl and water?
According to the equation:
C1 × V1 = C2 × V2
where C1 - the initial concentration, V1 - the volume of the initial solution, C2 - the final volume, V2 - the volume of the final solution.
From here, the volume of the initial solution required:
V1 = C2 × V2 / C1 = 250 ml × 0.20 M / 1.0 M = 50 ml
As a result, to prepare 250 ml of 0.20M NaCl, take 50 ml of 1.0M NaCl solution and add 200 ml of water.
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