a gaseous organic compound X was burnt in the excess of oxygen.A 0.112 dm3 sample of X measured at s.t.p produced 0.88 grams of CO2 how many carbon atoms are present in one molecule of x ?
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Expert's answer
2012-10-03T09:00:00-0400
If organic compound X has formula C(x)H(y)O(z), the reaction is C(x)H(y)O(z) + k O2 = x CO2 + (y/2) H2O
IUPAC has defined standard reference conditions as being 0 °C and 100 kPa (1 bar) R = 8.314×10−2 L*bar*K(-1)*mol(-1) pV = nRT n = pV/(RT) n(X) = 1 bar * 0.112 L / (8.314×10−2 L*bar*K(-1)*mol(-1) * 273 K) = 0.005 mol n(CO2) = 0.88 g / 44 g/mol = 0.02 mol
x = n(CO2)/n(X) = 0.02 / 0.005 = 4 Four carbon atoms are present in one molecule of X.
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Assignment Expert
21.10.20, 20:41
Dear Faiza, Questions in this section are answered for free. We can't
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Faiza
15.10.20, 21:26
I didn't get why we have to calculate the no of moles from general gas
equation and how did we know that they are for CO2?
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Dear Faiza, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.
I didn't get why we have to calculate the no of moles from general gas equation and how did we know that they are for CO2?
Leave a comment