If we have 200.0mL of gas at 17.0 C what will be the volume of this gas at 10.0 C
V1 = 200.0 mL = 0.2 L
T1 = 17.0oC + 273 = 290 K
V2 = unknown
T2 = 10.0oC + 273 = 283 K
P1 = P2 = const
Solution:
Since the pressure doesn't change, Charles' Law can be used.
Charles' Law can be expressed as: V1Â / T1Â = V2Â / T2
V1T2Â = V2T1
To find the final volume, solve the equation for V2:
V2 = V1T2/T1
V2 = (0.2 L × 283 K) / (290 K) = 0.1952 L = 195.2 mL
V2 = 195.2 mL
Answer: V2 = 195.2 mL
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