Answer to Question #154352 in Chemistry for Svet

Question

How many grams of copper are required to react with 45.0 grams of silver nitrate? Cu+ 2 AgNO3= Cu(NO3)2 + 2 Ag

Answer 1

Solution:

The balanced chemical equation:

Cu + 2AgNO₃= Cu(NO₃)₂ + 2Ag

According to the equation: n(Cu) = n(AgNO₃)/2

Moles of AgNO₃ = Mass of AgNO₃ / Molar mass of AgNO₃

The molar mass of AgNO₃ is 169.87 g mol^-1.

n(AgNO₃) = Moles of AgNO₃ = 45.0 g / 169.87 g mol^-1 = 0.2649 mol

n(Cu) = n(AgNO₃)/2 = 0.2649 mol / 2 = 0.13245 mol

Moles of Cu = Mass of Cu / Molar mass of Cu

The molar mass of Cu is 63.546 g mol^-1.

Hence,

Mass of Cu = Moles of Cu × Molar mass of Cu = 0.13245 mol × 63.546 g mol^-1 = 8.41667 g = 8.42 g

Mass of Cu is 8.42 grams.

Answer: 8.42 grams of copper (Cu) are required.