Answer to Question #154064 in Chemistry for Engilbert

Question

How many molecules of zinc sulfate monohydrate does a 5mL of vitamin have?

Answer 1

n = m/M

m (ZnSO₄^.H₂O) = 27.44/1000 = 0.02744 g

M (ZnSO₄^.H₂O) = 179.49 g/mol

n (ZnSO^.H₂O) = 0.02744/179.49 = 0.00015 mol

Each mole of matter contains 6.02214076×10²³ molecules.

Given amount of ZnSO^.H₂O is equal to: 0.00015 x 6.02214076×10²³ = 10²⁰ molecules.

10²⁰ molecules of zinc sulfate monohydrate does a 5mL of vitamin have