When 83.5 moles of calcium acetate are dissolved in enough water to make 710.3 milliliters of solution, what is the molarity of acetate ions? Answer in units of M
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Expert's answer
2012-10-01T10:06:53-0400
C(calcium acetate) = n(calcium acetate) / V(solution) = 83.5 moles / 0.7103 L = 117.6 moles/L = 117.6 M due to equation: Ca(CH3COO)2 = Ca(2+) + 2 CH3COO(-) C(acetate ions) = 2*C(calcium acetate) = 2*117.6 = 235.2 M
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