Question

When 83.5 moles of calcium acetate are dissolved in enough water to make 710.3 milliliters of solution, what is the molarity of acetate ions? Answer in units of M

Answer 1

C(calcium acetate) = n(calcium acetate) / V(solution) = 83.5 moles / 0.7103 L =
117.6 moles/L = 117.6 M
due to equation:
Ca(CH3COO)2 = Ca(2+) + 2
CH3COO(-)
C(acetate ions) = 2*C(calcium acetate) = 2*117.6 = 235.2 M

Answer: C(acetate ions) = 235.2 M