2.
a) P4 + 5O2 = 2P2O5
b) M (P4) = 123.89 g/mol
M (O2) = 32 g/mol
M (P2O5) = 283.89 g/mol
n (P4)= 1.33/123.89 = 0.01 mol
n (O2) = 5.07/32 = 0.16 mol
P4 is the limiting reagent in this reaction.
n (P2O5) = 2 x n (P4) = 2 x 0.01 = 0.02 mol
m (P2O5) = n x M = 0.02 x 283.89 = 5.68 g
3.
2C4H10 + 13O2= 8CO2 + 10H2O
M (C4H10) = 58.12 g/mol
T = 15 + 273 = 288 K
n (C4H10) = 450/58.12 = 7.74 g/mol
n (CO2) = 8/2 n (C4H10) = 8/2 x 7.74 = 30.96 mol
pV=nRT
R = 8.31 L⋅bar⋅K−1⋅mol−1
T = 15 + 273 = 288 K
V (CO2) = nRT/p = (30.96 x 3.14 x 288) / 0.95 = 29 471 L
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