Question

How many atoms are in 56.7 gram mg3p2

Answer 1

Solution:

Moles of Mg₃P₂ = Mass of Mg₃P₂ / Molar mass of Mg₃P₂

The molar mass of Mg₃P₂ is 134.88 g mol^-1.

Hence,

Moles of Mg₃P₂ = 56.7 g / 134.88 g mol^-1 = 0.4204 mol = 0.42 mol

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Number of atoms Mg₃P₂ = 0.42 mol × (6.022×10²³ atoms / 1 mol) = 2.53×10²³ atoms Mg₃P₂

Number of atoms Mg₃P₂= 2.53×10²³ atoms

Answer: 2.53×10²³ atoms are in 56.7 grams Mg₃P₂.