V1 = 4.20 L
T1 = 77oC + 273 = 350 K
P1 = P2 = 800. torr = const
V2 = 3.60 L
T2 = unknown
Solution:
Since the pressure doesn't change, Charles' Law can be used.
Charles' Law can be expressed as: V1 / T1 = V2 / T2
V1T2 = V2T1
To find the final temperature, solve the equation for T2:
T2 = V2T1 / V1
T2 = (3.60 L × 350 K) / (4.20 L) = 300 K
T2 = 300 K or 27oC
Answer: a gas sample occupies 3.60 L at 300 K (27oC).
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