You fill a rigid steel cylinder that has a volume of 20.0 L with nitrogen gas to a final pressure of
2.00 x 104 kPa at 28°C. Calculate the number of moles for the nitrogen gas, as described by the ideal gas law
Expert's answer
PV=nRT
n = PV/RT
R=8.314 L⋅Pa⋅K−1⋅mol−1
n (N2) = (2 x 104 x 103 x 20) / (8.314 x (28+273)) = 159 839 mol
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot