Question #149834

You fill a rigid steel cylinder that has a volume of 20.0 L with nitrogen gas to a final pressure of
2.00 x 104 kPa at 28°C. Calculate the number of moles for the nitrogen gas, as described by the ideal gas law

Expert's answer

PV=nRT

n = PV/RT

R=8.314 L⋅Pa⋅K−1⋅mol−1

n (N2) = (2 x 104 x 103 x 20) / (8.314 x (28+273)) = 159 839 mol


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