Answer to Question #148412 in Chemistry for eljay

Question

How many moles of carbon dioxide gas is produced when 20.5 grams of ethyl alcohol is burned?

Answer 1

Solution:

The balanced chemical equation is:

C₂H₅OH(l) + 3O₂(g) = 2CO₂(g) + 3H₂O(l)

According to the equation: Moles of C₂H₅OH = Moles of CO₂ / 2

Moles of C₂H₅OH = Mass of C₂H₅OH / Molar mass of C₂H₅OH

The molar mass of C₂H₅OH is 46.07 g mol^-1.

Hence,

Moles of C₂H₅OH = 20.5 g / 46.07 g mol^-1 = 0.445 mol

Moles of CO₂ = 2 × Moles of C₂H₅OH = 2 × 0.445 mol = 0.89 mol

0.89 moles of CO₂

Answer: 0.89 moles of carbon dioxide (CO₂) gas is produced.