Question

Calculate the mass of glucose and water required to make 250 grams of 25% solution of glucose?

Answer 1

Question#14447

Calculate the mass of glucose and water required to make 250 grams of 25% solution of glucose?

Solution:

m (solution) = 250g

ω(solution%) = 25%

m (solute) (Glucose) = x g

m (solvent) (water) = (250 - x) g

ω(solution%) = $\frac{m \text{ (solute)}}{m \text{ (solution)}} \times 100$

$$25 = \frac{x}{250} \times 100$$

Solving for x we get:

x = 62,5 g

m (solvent)(water) = 250 - 62,5 = 187,5g

Answer:

m (Glucose) = 62,5 g

m (water) = 187,5g