Initially it's imrtant to understand the mass of sodium chloride to be used for this solution.
Cm(NaCl)=m(solute)m(solute)+m(solvent)⋅100Cm (NaCl)=\frac{m(solute)}{m(solute)+m(solvent)}⋅100%Cm(NaCl)=m(solute)+m(solvent)m(solute)⋅100%=frac\{};{}
Assuming that 1 ml = 1 g (solution density is 1 g/ml)
10=х25⋅10010=\frac{х}{25}⋅10010=25х⋅100
х=2.5 g
Therefore, the mass of 2.5 g of NaCl has to mixed with 25 ml of water.
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