Initially it's imrtant to understand the mass of sodium chloride to be used for this solution.
"Cm (NaCl)=\\frac{m(solute)}{m(solute)+m(solvent)}\u22c5100%""%=frac\\{};{}"
Assuming that 1 ml = 1 g (solution density is 1 g/ml)
"10=\\frac{\u0445}{25}\u22c5100"
х=2.5 g
Therefore, the mass of 2.5 g of NaCl has to mixed with 25 ml of water.
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