Answer to Question #139208 in Chemistry for Richard

Question

On a certain time of day, the concentration of carbon monoxide,CO in the air over metro Manila reached 1.8x10^-5 g/l. Convert this concentration to mg/m^3

Answer 1

In order to convert from g/l to mg/m³, one can proceed by steps: first, convert to mg/l and then convert mg/l to mg/m³.

In 1g, there is 1000 mg . Therefore, to convert from g to mg, you need to multiply the number in g by 1000:

$1.8\cdot10^{-5} \text{ g/l} = 1.8\cdot10^{-2} \text{ mg/l}$ .

1l is 1dm³. In its turn, 1dm³ is 1/1000 of 1m³. Therefore, to convert from l to m³, you multiply the number in l by 1/1000:

$\frac{1.8\cdot10^{-3} \text{ mg}}{1\text{ l}} = \frac{1.8\cdot10^{-3} \text{ mg}}{1/1000\text{ m}^3} = 1.8 \text{ mg/m}^3$ .

Answer: the concentration is 1.8 mg/m³.