When left over a flame a marshmallow is consumed in a combustion reaction. Assuming a marshmallow is made of entirely sucrose, C12H22O11, and after combustion no residual solid remained, the following chemical equation describes this reaction.
C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(g)
Using the chemical equation in Question 1 above, if a second marshmallow was measured and contained 6.94 g of sucrose and is the limiting reactant, what is the theoretical yield, in g, of CO2?
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Expert's answer
2020-10-19T14:27:46-0400
C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(g)
The mass of carbon dioxide produced in the reaction can be calculated as following:
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