The combustion of glucose can be described as following:
C6H12O6 + 6O2 = 6CO2 + 6H2O
According to the reaction, six moles of carbon dioxide are produced from one mole of glucose. As a result, combustion of 1.4 mol of glucose results in the formation of 6 × 1.4 mol = 8.4 mol of carbon dioxide.
Answer: 8.4 mol
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