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Answer to Question #136028 in Chemistry for jay

Question #136028
During normal conditions the respiratory gases were mixed 25 dm3 of carbon dioxide with 10 dm3 of oxygen. Express the composition of gas mixture in the volume percentage.
1
Expert's answer
2020-09-30T07:54:57-0400

Total volume: 25=10=35 dm3

Volume percentage of carbon dioxide: 25/35x100=71.4%

Volume percentage of oxygen: 10/35x100=28.6%


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