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Answer to Question #136028 in Chemistry for jay
Question #136028
During normal conditions the respiratory gases were mixed 25 dm3 of carbon dioxide with 10 dm3 of oxygen. Express the composition of gas mixture in the volume percentage.
Expert's answer
Total volume: 25=10=35 dm3
Volume percentage of carbon dioxide: 25/35x100=71.4%
Volume percentage of oxygen: 10/35x100=28.6%
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