Answer to Question #134250 in Chemistry for Shalom Garcia

Question

Calculate the number of liters of Hydrogen gas at STP that would be produced by the reaction of 6.20g of Magnesium with excess at HCl.

Mg+2HCl➡️MgCl2+H2

Answer 1

As HCl is in excess, Mg will be the limiting reagent for this reaction.

n = m/M

M(Mg)=24.3 g/mol

n (Mg) = 6.20/24.3 = 0.3 mol

n (H₂)=n (Mg) = 0.3 mol

n (H₂) = V/22.4

V(H₂) = n (H₂) x 22.4 = 0.3 x 22.4 = 6.7 l