Answer to Question #131224 in Chemistry for Kyle Sumicad

Question

What volume of 0.558 M

Answer 1

This question is only part of some task.

General solution:

1^st Case:

What volume of 0.558 M A contains X moles of A.

Where A is some substance, X is the amount of a given substance.

Molarity of A = Moles of A / Volume of A

Then,

Volume of A = Moles of A / Molarity of A

Volume of A = Moles of A / 0.558 M

2^nd Case:

"What volume of 0.558 M" - this is the beginning of a more complicated task.

Such as: "What volume of 0.558 M HNO₃ solution is required to react completely with 45.55 mL of 0.0515 M Ba(OH)₂?

Then,

Ba(OH)₂ + 2HNO₃ = Ba(NO₃)₂ + 2H₂O

Moles of Ba(OH)₂ = (0.04555 L)(0.0515 mol/L) = 0.002346 mol

According to the equation: Moles of Ba(OH)₂ = Moles of HNO₃ / 2

Moles of HNO₃ = 2 * Moles of Ba(OH)₂ = 2 * (0.002346 mol) = 0.004692 mol

Volume of HNO₃ = Moles of HNO₃ / Molarity of HNO₃

Volume of HNO₃ = (0.004692 mol) / (0.558 M) = 0.0084 L = 8.4 mL

V(HNO₃) = 8.4 mL

However, to answer this question correctly requires a full question.