Question #129507

In the reaction nh3(g)+o2-->no(g)+h2o(g)
How many grams of h2o are generated when 1.54 moles of nh3 react?

Expert's answer

4nh3(g)+5o2-->4no(g)+6h2o(g)

n (h2o) = 1.54/4 x 6 = 2.31 mol

M (h2o) = 18 g/mol

m (h2o) = n x M = 2.31 x 18 = 41.58 g


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