Considering the limiting reactant, what is the volume of NO gas produced from 60.0 L of ammonia gas and 50.0 L of oxygen gas? (Assume constant conditions.)
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
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Expert's answer
2012-09-14T09:07:57-0400
Volume of reactants is proportional to coefficient in equation. So for this reaction we need correlation of volumes NH3 : O2 like 4:5 and we have 60:50,so NH3 is in excess,and O2 is limiting reactant
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